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3 years ago

How many g of silver chloride will be produced by reacting 10g of silver nitrate with sodium chloride?

Chemistry

2 answers:

I am Lyosha [343]3 years ago

7 0

Answer:

16.8 g of AgCl are produced

Explanation:

The reactants are: NaCl and AgNO₃

The products are: AgCl, NaNO₃

Balanced equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s) ↓

We convert the mass of AgNO₃ to moles → 10 g / 85g/mol = 0.117 moles

Ratio is 1:1, therefore 0.117 moles of nitrate will produce 0.117 moles of AgCl.

According to stoichiormetry.

We convert the moles to mass → 0.117 mol . 143.3g /1mol = 16.8 g

kiruha [24]3 years ago

6 0

Answer:

8.44 grams of silver chloride will be produced

Explanation:

Step 1: Data given

Mass of silver nitrate = 10.0 grams

Molar mass of silver nitrate = 169.87 g/mol

Molar mass of silver chloride = 143.32 g/mol

Step 2: The balanced equation

AgNO3 + NaCl → NaNO3 + AgCl

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 10.0 grams / 169.87 g/mol

Moles AgNO3 = 0.0589 moles

Step 4: Calculate moles AgCl

For 1 mol AgNO3 we need 1 mol NaCl to produce 1 mol NaNO3 and 1 mol AgCl

Step 5: Calculate mass AgCl

Mass AgCl = moles AgCl * molar mass AgCl

Mass AgCl = 0.0589 moles * 143.32 g/mol

Mass AgCl = 8.44 grams

8.44 grams of silver chloride will be produced

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The relationship between pressure and solubility of the gas is given by Henry's law as:

$S_g = kP_g$

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$S_g$ is the solubility of the gas.

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3 years ago

Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor

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Answer: Fe - O

Explanation:

1) Start by showing the chart information in a more understandable way:

Elements ---------- Electronegativity

aluminum (Al) ----- 1.61

calcium (Ca) ------- 1

carbon (C) ---------- 2.55

chlorine (Cl) -------- 3.16

fluorine (F) --------- 4

hydrogen (H) ------ 2.2

iron (Fe) ------------- 1.83

nitrogen (N) --------- 3.04

oxygen (O) ----------- 3.44

phosphorus (P) ----- 2.19

potassium (K) -------- 0.82

silicon (Si) ------------- 1.9

sulfur (S) --------------- 2.58

2) Find the electronegativity differences for the atoms in each compound:

i) Ca – Cl: 3.16 - 1 = 2.16

ii) Fe – O: 3.44 - 1.83 = 1.61

iii) H – S: 2.58 - 2.2 = 0.38

iii= F – F = 4 - 4 = 0

3) Analysis

i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.

ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.

iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.

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