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KiRa [710]
3 years ago
14

What is an isotope ? And how do we use it ?

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
Somewhat of the same element, have same amount of protons but different number of neutrons. <span />
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A 0.1873 g sample of a pure, solid acid, H2X (a diprotic acid) was dissolved in water and titrated with 0.1052 M NaOH solution.
puteri [66]

Answer:

We need 41.8 mL of NaOH

Explanation:

<u>Step 1:</u> Data given

Mass of H2X = 0.1873 grams

Molarity of NaOH solution = 0.1052 M

Molar mass of H2X = 85.00 g/mol

<u>Step 2</u>: The balanced equation

H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)

<u>Step 3:</u> Calculate moles of H2X

Moles H2X = mass H2X / Molar mass H2X

Moles H2X = 0.1873 grams / 85.00 g/mol

Moles H2X = 0.0022 moles

<u>Step 4:</u> Calculate moles of NaOH

For 1 mol H2X we need 2 moles NaOH to produce 1 mole of Na2X and 2 moles of H2O

For 0.0022 moles of H2X we need 0.0044 moles of NaOH

<u />

<u>Step 5</u>: Calculate volume of NaOH

Volume of NaOH = moles of NaOH / molarity of NaOH

Volume of NaOH = 0.0044 moles / 0.1052 M

Volume NaOH =  0.0418 L = 41.8 mL

We need 41.8 mL of NaOH

6 0
3 years ago
Compare the seasons on Titan to the seasons on Earth.
kiruha [24]
Since Titan orbits roughly along Saturn's equatorial plane, and Titan's tilt relative to the sun is about the same as Saturn's, Titan's seasons are on the same schedule as Saturn's—seasons that last more than seven Earth years, and a year that lasts 29 Earth years.
6 0
2 years ago
What are the reactants in a neutralization reaction? two elements an acid and a base an element and a compound a salt and water
Vitek1552 [10]

ok thank you for elaborating and you are correct in a neutralization reaction the reactants are the acid and base. the salt and water would be the product and the two elements could be anything meaning that it is most likely a mixture

Hope this helps

5 0
3 years ago
Read 2 more answers
Which of the following measurements has FOUR significant figures?
garik1379 [7]

Answer:

A) 0.1005 m

sorry if it's wrong

7 0
3 years ago
How much concentrated solution would it take to prepare 2.75 L of 0.400 M HCl upon dilution with water
grin007 [14]
Hydrochloric acid is usually purchased in a concentrated form that is 37.0% HCl by mass and has a density of 1.20g/mL. Calculate the molarity of the concd HCl.
1.20 g/mL x 1000 mL x 0.37 x (1/36.5) = about 12 M or so but you do it exactly.

Then mL x M = mL x M
mL x 12 M = 2800 mL x 0.475
Solve for mL of the concd HCl solution.
7 0
2 years ago
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