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KiRa [710]
3 years ago
14

What is an isotope ? And how do we use it ?

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
Somewhat of the same element, have same amount of protons but different number of neutrons. <span />
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Consider the sulfur difluoridemolecule.What is the central atom? Enter its chemical symbol.How many lone pairs are around the ce
olchik [2.2K]

Answer:

a. The central atom is sulfur

b. SF2

c. The central atom has two lone pairs

d. The ideal angle between the sulfur-fluorine bonds is 109.5°

e.  I expect the actual angle between the sulfur-fluorine bonds to be less than 109.5° because unbonded pairs repel bonded pairs more than bonded pairs repel other bonded pairs. So the bonds here will be pushed closer than normal

8 0
3 years ago
If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
Lynna [10]

Answer:

32 mols of water

Explanation:

2H2 + O2 ==> 2H2O

What your givens are telling you and what the equation is saying is that

for every mol of O2, you get 2 mols of H2O

So you could do it with the proportion about.

1/16 = 2/x                 Cross multiply

x = 16 * 2

x = 32

3 0
3 years ago
Read 2 more answers
A chemical bond joins atoms or electrons? together in a molecule
Schach [20]
Electrons basically ARE the chemical bond.  The atoms are joined together by the bonds.
4 0
3 years ago
For the process 2SO2(g) + O2(g) --&gt; 2SO3(g),
CaHeK987 [17]

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

\Delta G = \Delta H - T \Delta S

where

\Delta G is the Gibbs free energy

\Delta H is the change in enthalpy of the reaction

T is the absolute temperature

\Delta S is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

8 0
3 years ago
How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid acc
natulia [17]

The balanced equation for the reaction is as follows

Cu₂O + 2HCl ---> 2CuCl + H₂O

Molar ratio of Cu₂O to CuCl is 1:2

mass of Cu₂O reacted - 73.5 g

Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

According to the molar ratio,

when 1 mol of  Cu₂O reacts then 2 mol of CuCl is formed

therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

number of CuCl moles formed - 1.02 mol

mass of CuCl formed - 1.02 mol x 99 g/mol = 101 g

mass of CuCl formed is 101 g

6 0
3 years ago
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