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dmitriy555 [2]
3 years ago
7

How does one calculate the pH of a solution? O A. The pH is the product of [H+] and [OH-]. O B. The pH is the negative log of [O

H-]. O c. The pH is the log of [H+). D. The pH is the negative log of [ht].​
Chemistry
1 answer:
blagie [28]3 years ago
8 0

Answer:

I believe it is A

Explanation:

pH = -log[H+] and pOH = -log[OH−].    

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Is a compound a metal or non metal
VARVARA [1.3K]

Answer:

Compounds between Nonmetals and Nonmetals

Compounds that consist of a nonmetal bonded to a nonmetal are commonly known as Molecular Compounds, where the element with the positive oxidation state is written first. In many cases, nonmetals form more than one binary compound, so prefixes are used to distinguish them.

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3 years ago
A naturally occurring element consists of three isotopes. The data for the isotopes are:
max2010maxim [7]
(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =

</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
7 0
3 years ago
WHAT IS THE PH OF LEMON JUICE IF IT HAS A HYDROGEN ION CONCENTRATION [AT]ON[H^ + ]=5.0*10^ -2 M.
stellarik [79]

Answer:

ph=2

Explanation:

8 0
3 years ago
Suppose that CaO is added as an impurity to Li2O. If the Ca2+ substitutes for Li+, what kind of vacancies would you expect to fo
Leno4ka [110]

Answer:

Positive charges are eliminated by creating lithium vacancies, and for every Ca2+ ion added, a single lithium vacancy is formed.

Explanation:

The addition of calcium oxide as an impurity to lithium oxide creates an  interstices due to the replacement of the Lithium ion by calcium ion. The creation of  interstices is as a result of  the replacement of the positive ions (Lithium by calcium). To make the reaction neutral, these replacements must occur  when the interstices are formed

6 0
3 years ago
The density of a 45.0 mass % solution of ethanol (C2H5OH) in water is 0.873 g/mL. What is the molarity of the solution?
antoniya [11.8K]

Answer : The concentration of solution is, 8.53 M.

Explanation :

As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{0.873g/mL}=114.5mL

Now we have to calculate the molarity of solution.

Mass of C_2H_5OH = 45.0 g

Volume of solution = 114.5 mL

Molar mass of C_2H_5OH = 46.07 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{45.0g\times 1000}{46.07g/mole\times 114.5mL}=8.53mole/L=8.53M

Therefore, the concentration of solution is, 8.53 M.

6 0
3 years ago
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