Short Answer: A
Remark
The second cut is going to have the same slope as the original line. The lines are parallel.
Step One
You need to find the slope. That is the main part of this problem. You can pick any 2 points on the graph to do that.
<em>Point one</em>
(- 11, 10) That point is on the upper left of the line
<em>Point Two</em>
The y intercept is a handy point in this question. It is right on the y axis. Each square counts as 2, so it is at (0,6)
<em>Formula</em>
slope = m = (y2 - y1) / (x2 - x1)
<em>Givens</em>
y2 = 10
y1 = 6
x2 = -12 Each square counts as 2 in the x direction.
x1 = 0
<u>Substitute and solve.</u>
m = (10 - 6) / (-12 - 0)
m = 4/ - 12
m = - 1/3
Step Two
Find the y intercept of the new line using the given point.
So far what we have is
y = (-1/3)x + b
The point used for the second line is (0,-2)
-2 = (-1/3)*0 + b
b = - 2
Answer
The second line is
y = (-1/3)x - 2
So, we have that the final value of the zero coupon bond after ten years will be 3000$. The TIPS mature after 10 years, but the interest will be calculated only for 5 years. Each year of interest, the TIPS gains 2%*2500=2*25=50$. Hence the TIPS gains 50$ for each year of interest. Since the interest is not compounding, it will gain 5*50=250$ in value. Hence its total value after ten years is 2500+250=2750$. The total maximum value of the two assets combined is 3000+2750=5750$ and it is attained after 10 years. If one things that money is more important now than in 10 years, the assets could be sold at a lower price; nonetheless their max value never exceeds choice d)=5.750$
T(n)=n×12, where n=the nth term in the sequence and where 12=a constant. always by 12
I think the answer is B.It is a space telescope
Answer:
Given point (5,-12) falls into IV quadrant
<u>The right triangle with legs of 5 and -12, and hypotenuse is:</u>
- √5² + (-12)² = √25+144 = √169 = 13
<u>Value of sinθ, cosθ, and tanθ:</u>
- sin θ = -12/13
- cos θ = 5/13
- tan θ = -12/5
