The acceleration of the particle is given by the formula mentioned below:
Differentiate the position vector with respect to t.
Differentiate both sides of the obtained equation with respect to t.
Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.
The initial position is obtained at t=0. Substitute t=0 in the given position function.
Answer:
Step-by-step explanation:
Okay, so hopefully my crude diagram helps you visualize the problem. When in doubt, always draw a picture.
All I did was graph the points and formed a line.
Slope: It's going to be 0 because it doesn't change at all (no different y values)
(y2-y1)/(x2-x1) = (6-6) / (4-2) = 0/2 = 0
Y intercept is where the line crosses the y axis- this is also where x=0 (find it in your chart!)
Equation is y= 6; I don't know how to explain this, but trust me, it's right
