To understand this problem, you must first understand the definition of domain and range. Domain is all possible x values (possible input), and range is all possible y values (possible output). Based on this, we can now sort the terms as the following:

Domain

Independent variable
Input value
X-value

Range

Dependent variable
Y-value
Output value

Hope this helps!!

4 0

2 years ago

5. Solve 6(x - 1) = 6x - 6

MatroZZZ [7]

Answer:

Its infinite solutions because its the same exact thing when you simplify the first half of the problem.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$

3 0

3 years ago