<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
Answer:
It would be 30 bc that are the same size on both side
Answer:
6x^2 + 4x
Step-by-step explanation:
g(x) + f(x)
= -8x^2 - 3x + 5 + 2x^2 + 7x - 5
= -8x^2 + 2x^2 - 3x + 7x + 5 - 5
= - 6x^2 + 4x
Answer:
The probability is 0.33696
Step-by-step explanation:
The probability that the outcome will be heads x times is calculated using the following equation:
nCx is calculated as:
This apply for variables that follows a binomial distribution. In which we have n independent and identical events with two possibles results: success and fail with a probability p and 1-p respectively.
So, In this case, n is equal to 5, and p is equal to 0.6 because we are going to call success the event in which the outcome of the coin is head.
Then, the probability that the outcome will be heads at least 4 times is calculated as:
P = P(4) + P(5)
Where P(4) is:
P(4)=0.2592
And P(5) is:
P(4)=0.07776
Finally, the probability is:
P = 0.2592 + 0.07776
P = 0.33696
The answer is: [D]: 2x + 22 .
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