Here is the full question:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
Answer:
95.30 %
Explanation:
equation for the reaction is given as:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.00 g of Cu = 
= 0.01574 mol of Cu
10 mL of 16 M HNO3 = 
= 0.16 mol of HNO3
However, from both variables; we can arrive at a conclusion that Cu is the limiting reagent.
therefore % yield = = 4.70 %
Percentage yield = 
Percentage yield = 
%
Percentage yield = 0.953 × 100%
Percentage yield = 95.30 %
Answer:
4 Fe + 3 O2 = 2 Fe2O3
Explanation:
In order to balance the equation, there should be equal number of iron atoms (Fe) and oxygen atoms (O2) in Iron(III) oxide (Fe2O3).
Since there are two atoms of Oxygen in 1 oxygen molecule and 3 atoms of Oxygen in 1 Iron Oxide, the least common multiples of the total oxygen atoms which would equal each other is 6 atoms of Oxygen. This results in 3 molecules of O2 and 2 molecules of Fe2O3.
In order to balance out the amount of iron in iron oxide, you must then calculate the total iron atoms in iron oxide; since there are 2 atoms of Fe in each molecule of Iron Oxide and there is 2 molecules of Fe2O3, the total is 2*2 = 4 atoms of iron, Fe.
In order to get 4 atoms of iron from molecules of Fe, you need 4 molecules of Fe, since each molecule contains 1 Fe.
Answer:
D. A boulder falling off a tall cliff
Explanation:
The boulders potential energy transforms to kinetic energy as the boulder falls.
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