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frutty [35]
3 years ago
15

PLEASE HELP 2) Common Factors: 2 cups = 1 pint 2 pints = 1 quart 4 quarts = 1 gallon

Chemistry
1 answer:
lyudmila [28]3 years ago
6 0
I think the answer might be 6 cups
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Lead (ll) nitride+ammonium sulfate > lead(ll) sulfate + ammonium nitride
Alenkinab [10]

Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

7 0
4 years ago
what is moltarity of a solution made from dissolving 3.0 moles of saline (NaCl) in 0.25 L of solution
stiks02 [169]
It is 12 to 1 or 12/1 miles of saline to L solution
8 0
3 years ago
The normal freezing point of water is 0.00 ⁰C. What is the freezing point of a solution containing450.0 mg of ethylene glycol (M
anyanavicka [17]

Answer:

Freezing T° of solution = - 8.98°C

Explanation:

We apply Freezing point depression to solve this problem, the colligative property that has this formula:

Freezing T° of pure solvent - Freezing T° of solution = Kf . m

Kf = 1.86°C/m, this is a constant which is unique for each solvent. In this case, we are using water

m = molality (moles of solute / 1kg of solvent)

We convert the mass of solvent from g to kg

1.5 g . 1kg/1000g = 0.0015 kg

We convert the mass of solute, to moles. Firstly we make this conversion, from mg to g → 450mg . 1g/1000mg = 0.450 g

0.450 g. 1mol / 62.07g = 7.25×10⁻³ moles

Molality → 7.25×10⁻³ mol / 0.0015 kg = 4.83 m

- Freezing T° of solution = 1.86°C /m . 4.83 m - Freezing T° of pure solvent

-Freezing T° of solution = 1.86°C /m . 4.83 m - 0°C

Freezing T° of solution = - 8.98°C

8 0
3 years ago
Read 2 more answers
Is the following chemical equation balanced? 2Na + 2H2O 2NaOH + H2
Mumz [18]

yes because you have 2 H 2Na 2O on both sides


8 0
3 years ago
Read 2 more answers
Given the incomplete equation 4Al + 3O2 → 2X, what compound is X?
Sever21 [200]
<h3><u>Answer</u>;</h3>

B) Al2O3

<h3><u>Explanation;</u></h3>

Aluminium reacts with oxygen to form aluminium oxide.

The chemical reaction for the reaction between Aluminium and Oxygen is;

4Al+ 3O₂→ 2Al₂O₃

Therefore;

Compound X is Aluminium oxide (Al₂O₃)

8 0
4 years ago
Read 2 more answers
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