Answer:
The volume of the sample is 17.4L
Explanation:
The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:
0.1800mol + 0.1800mol reactants =
0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.
Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:
V1n2 = V2n1
<em>Where V is volume and n moles of 1, initial state and 2, final state of the gas</em>
Replacing:
V1 = 23.2L
n2 = 0.2700 moles
V2 = ??
n1 = 0.3600 moles
23.2L*0.2700mol = V2*0.3600moles
17.4L = V2
<h3>The volume of the sample is 17.4L</h3>
Answer:
nucleus and electrons
Explanation:
nucleus contains protons and neutrons
Answer:
8700
Explanation:
First, do the operations i<em>nside parentheses</em>.
102 900/12 = 8600 2 sfs because of 12
170/1.27 = 130 2 sfs because of trailing 0 in 170
===============
Now, do the addition.
8600
<u> + </u><u>13</u><u>0
</u>
8700
The answer has two significant figures because when adding, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
The last significant figure in 8600 (the 6, in the hundreds place) is further to the left than the last significant figure in 130 (the 3, in the tens place).
We round off to the nearest hundred and get the answer, 8700.
Crystal<span> of tetrahedrally bonded carbon atoms in a </span>covalent network lattice<span> witch </span>crystallizes<span> into the diamond </span>lattice.
Answer:
385.69 g of O₂
Solution:
The Balance Chemical equation for said reaction is as follow;
2 H₂ + O₂ → 2 H₂O
According to Equation,
4.032 g ( 2 mol) H₂ reacts to produce = 36.03 g (2 mol) of H₂O
So,
48.6 g H₂ on reaction will produce = X g of H₂O
Solving for X,
X = (48.6 g × 36.03 g) ÷ 4.032 g
X = 434.29 g of H₂O
It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).
So, According to Equation,
36.03 g (2 mol) H₂O is produced by = 31.998 g (1 mol) of O₂
So,
434.29 g of H₂O will be produced by = X g of O₂
Solving for X,
X = (434.29 g × 31.998 g) ÷ 36.03 g
X = 385.69 g of O₂
