<span>Normally when they tell you interest rate they say per annum meaning the percent interest rate for a year.
But in this problem they seem to say John pays 12% for a 146 day loan.
So interest = P * r / 100 = 8400 * 12/100 = $1,008.00
Maturity value = Principal + Interest = 8400 + 1008 = $9,408.00</span>
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As a rule , - times - = + and - times + = -

Therefore the correct answer to the question is 2m squared n
It moves the graph 5 steps downwards on the y axis.
Answer:
Rolling case achieves greater height than sliding case
Step-by-step explanation:
For sliding ball:
- When balls slides up the ramp the kinetic energy is converted to gravitational potential energy.
- We have frictionless ramp, hence no loss due to friction.So the entire kinetic energy is converted into potential energy.
- The ball slides it only has translational kinetic energy as follows:
ΔK.E = ΔP.E
0.5*m*v^2 = m*g*h
h = 0.5v^2 / g
For rolling ball:
- Its the same as the previous case but only difference is that there are two forms of kinetic energy translational and rotational. Thus the energy balance is:
ΔK.E = ΔP.E
0.5*m*v^2 + 0.5*I*w^2 = m*g*h
- Where I: moment of inertia of spherical ball = 2/5 *m*r^2
w: Angular speed = v / r
0.5*m*v^2 + 0.2*m*v^2 = m*g*h
0.7v^2 = g*h
h = 0.7v^2 / g
- From both results we see that 0.7v^2/g for rolling case is greater than 0.5v^2/g sliding case.