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Kisachek [45]
3 years ago
14

Can someone help me on how to do this i have a whole worksheet of this and i have no clue what to do

Mathematics
1 answer:
ss7ja [257]3 years ago
4 0

Answer:

a & b.    in 1 sec the object reaches a maximum height of 16 feet

c.      2 sec. the object will hit the ground

Step-by-step explanation:

h = -16t^{2} +32t.

When graphed, you would get a parabola that opens down.  The vertex is the key to the problem.  The vertex (t, h) will give you the maximum height and the time to reach that height.

So,  t = -b/2a = -32/-16(2) = 1

      h(1) = -16(1^{2}) + 32(1) = -16 + 32 = 16

Therefore, the vertex is (1, 16)

So, in 1 sec the object reaches a maximum height of 16 feet

let h = 0 for when the object hits the ground

-16t^{2} +32t = 0

-16t(t - 2) = 0

t = 0  or t = 2

After 2 sec. the object will hit the ground

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