The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.
<h3>How to calculate probability?</h3>
The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:
= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]
= 42/220 + 18/66
= 0.1909 + 0.2727
= 0.4179
In conclusion, the probability is 0.4179.
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brainly.com/question/24756209
Answer:
55 kg
Step-by-step explanation:
lose 2kg per 3 week
for 12 weeks
3×4=12
4×2=8
61-8=53
1kg per week gained for 2 weeks = 2kg
53kg + 2 kg =55kg
Hope you understand...
Answer:
(6.3*10³) ÷ (1.8*10⁵)
6.3*10³ = 0.063*10⁵
then:
(6,3*10³) ÷ (1.8*10⁵) = (0.063*10⁵) ÷ (1.8*10⁵)
= 0.063/1.8
= 0.035
0.035 = 3.5 *10⁻² = 35*10⁻³
Group 8 atoms have the highest number of electrons compare to others in its period
