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3 years ago

Please help asap, will mark brainlest. Thanks

Mathematics

1 answer:

mixer [17]3 years ago

3 0

Answer:

4x^2 + 4 - 5x + x - 2x^2 + 8

= (4x^2 - 2x^2) + (x - 5x) + (4 + 8)

= 2x^2 - 4x + 12

=> D is correct

2x^2 + 6x - 7x + 8 - 3x^2 + 1

= (2x^2 - 3x^2) + (6x - 7x) + (1 + 8)

= -x^2 - x + 9

=> C is correct

B is correct (4 and 3)

Hope this helps!

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Pleeeeeeessssssseeee help

lozanna [386]

Answer:

0.25, 5/8, 11/16

Step-by-step explanation:

1st, make all of them to decimal or fraction (recommended). I will do decimal this time because it's easier. 11/16 = 0.6875; 5/8 = 0.625 . So we can easily get which one is bigger or smaller.

5 0

3 years ago

Read 2 more answers

A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $30 an hour for his own labo

Korvikt [17]

Answer:

The plumber worked 50 hours, and his assistant worked 25 hours.

Step-by-step explanation:

Since a plumber and his assistant work together to replace the pipes in an old house, and the plumber charges $ 30 an hour for his own labor and $ 20 an hour for his assistant's labor, and the plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $ 2000, to determine how long did the plumber and his assistant work on this job the following calculation must be performed:

40 x 30 + 20 x 20 = 1200 + 400 = 1600

50 x 30 + 25 x 20 = 1500 + 500 = 2000

Therefore, the plumber worked 50 hours, and his assistant worked 25 hours.

6 0

2 years ago

A hovercraft takes off from a platform. It’s height (in meters), x seconds is modeled by h(x)=-(x-11)(x+3). What is the height o

Eddi Din [679]

Answer:

The height of the hovercraft at the time of takeoff is 33 meters.

Step-by-step explanation:

Height of hovercraft x seconds after takeoff = h(x) = -(x - 11)(x + 3)

Height after takeoff is = h(0) = -(0 - 11)(0 + 3) = -(-11)(3) = 33

So the correct answer is 33 meters. The height of the hover craft at the time of the takeoff is 33 metres.

Answer: 33 meters.

Please mark brainliest

Hope this helps

6 0

3 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago

Can someone help me pleaseee?

Soloha48 [4]

(2,4) cause where the lines meet

4 0

3 years ago

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