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mixer [17]
3 years ago
11

Pleeeeeeessssssseeee help​

Mathematics
2 answers:
Inga [223]3 years ago
6 0

Hey!

------------------------------------------------

Turn each width into a decimal.

0.25

11/16 = 0.6875

5/8 = 0.625

Now, put from least to greatest.

0.25, 5/8, 11/16

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{0.25,~5/8,~11/16}}

------------------------------------------------

Hope This Helped! Good Luck!

lozanna [386]3 years ago
5 0

Answer:

0.25, 5/8, 11/16

Step-by-step explanation:

1st, make all of them to decimal or fraction (recommended). I will do decimal this time because it's easier. 11/16 = 0.6875; 5/8 = 0.625 . So we can easily get which one is bigger or smaller.

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Read 2 more answers
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
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1. -3x + -6
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