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hodyreva [135]
3 years ago
5

HELP ME PLZ NOT A TEST !!!!!!!!!!!!!!!!! ITS A REVIEW AND I DONT GET IT I NEED TO KNOW THE STEPS AND THE AWNSER

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer: See below

Step-by-step explanation:

1. For this problem, you see that it's 5². The only problem that displays 5² is A². Now, there is a ×3 after that. That means there is 3 of 5². If you are still not sure, you can solve the problem.

5²×3=25×3=75

A shows 75.

-----------------------------------------------------------------------------------------------------------------

2. You need to first distribute each factor and then combine like terms.

-14a+10b+20a-32b+2

6a-22b+2

B

-----------------------------------------------------------------------------------------------------------------

3. You need to first distribute each factor and then combine like terms.

-6n+30+18n-12

12n+18

D

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Rewrite the following in the form log(c).<br> log(10) – log(5)
Svet_ta [14]

Answer:

log(2)

Step-by-step explanation:

In order to combine log(10) and log(5), you need to look at the sign that's combining them. In this example, it is a subtraction sign. When two logs are being subtracting from each other, it's the same as dividing the two. You would rewrite it like this:

log(10/5)

You would then solve 10/5, and get 2. You would rewrite the log as:

log(2)

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3 years ago
A school assembly had 25 students in attendance, and 20% of them were first-graders. How many first-graders were at the assembly
artcher [175]

Answer:

5

Step-by-step explanation:

20%=0.2

25 x 0.2 = 5

5 0
3 years ago
At the store, Martin buys a bottle of juice for $2.99, a pound of cheese for $5.45, and a bunch of grapes for $1.70. What is the
Alla [95]

Answer:

10.14

Step-by-step explanation:

4 0
3 years ago
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The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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3 years ago
What is the value of x?
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Answer:

i think its 8

Step-by-step explanation:

5 0
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