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hodyreva [135]
3 years ago
5

HELP ME PLZ NOT A TEST !!!!!!!!!!!!!!!!! ITS A REVIEW AND I DONT GET IT I NEED TO KNOW THE STEPS AND THE AWNSER

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer: See below

Step-by-step explanation:

1. For this problem, you see that it's 5². The only problem that displays 5² is A². Now, there is a ×3 after that. That means there is 3 of 5². If you are still not sure, you can solve the problem.

5²×3=25×3=75

A shows 75.

-----------------------------------------------------------------------------------------------------------------

2. You need to first distribute each factor and then combine like terms.

-14a+10b+20a-32b+2

6a-22b+2

B

-----------------------------------------------------------------------------------------------------------------

3. You need to first distribute each factor and then combine like terms.

-6n+30+18n-12

12n+18

D

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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

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yuradex [85]

Answer:

Answer is option 2

Step-by-step explanation:

We know that Angle M = Angle G (given in diagram)

We also know that Angle L in triangle LMN is equal to Angle L in triangle LGH

As two angles are equal in both triangles they are similar.

But why is it Triangle LGH instead of Triangle HGL?

As we know M=G therefore they should be in the same place in the name Of the triangle. In triangle LMN M is in the middle therefore Angle G should also be in the middle

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3 years ago
Solve the triangles for X: include the steps if you can
MAXImum [283]

Answer:

10) x=9

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Step-by-step explanation:

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10)   2x+8x+90=180

10x=90

x=9

11) 3x+1+2x+2+2x+2=180

7x+5=180

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x=25

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3 years ago
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well you cant chose what gender your child will turn up so it can be b/b (boy, boy) g/b, g/g, b/g

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3 years ago
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