Solve. If there are X teams in a sports league and all the teams play each other twice, a total of N(x) gamers are played, where
N(x)=x^2-x. A soccer league has 10 teams, each of which plays the others twice. If the league pays $46 per game for the field and officials, how much will it cost to play the entire schedule?
According to the problem, <em>x </em>refers to teams, and represents numbers of games played.
So, if there are 10 teams, we just have to replace this value for the <em>x</em> and calculate the number of games. Once we have it, we multiply all games by $46, which is the cost per game.
This means that in the entire schedule there are 90 games. If each one costs $46, the whole schedule will cost: