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3 years ago

Is it A. 10 B.-9 C.3 D.6

Mathematics

2 answers:

elixir [45]3 years ago

8 0

Answer:

C. 3

Step-by-step explanation:

You know the angle sum is ...

∠FGT +∠TGH = ∠FGH

You can use this relation with the given values to find x.

90 + (8x +4) = 39x +1

93 = 31x . . . . . . . . . . . . . add -1-8x, collect terms

3 = x . . . . . . . . . . . . . . . . divide by 31

stellarik [79]3 years ago

6 0

Answer:

C) x=3

Step-by-step explanation:

(39x+1)-90=8x+4

39x+1-90=8x+4

39x-8x-89=4

31x=4+89

31x=93

x=93/31

x=3

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Answer:

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Step-by-step explanation:

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3 years ago

Solve the following proportions X/5=8/120

frez [133]

Answer:

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Step-by-step explanation:

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2 years ago

Leroy took a total of 10 pages of notes during 5 hours of class. In all, how many hours will Leroy have to spend in class before

Ivanshal [37]

Answer:

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3 years ago

Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Since

$\\ f(36) = \frac{6}{25}$

And

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Then, the function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

8 0

3 years ago