Green Line:
This is a horizontal line at x = 0, so it would be:
x ? 0
Since the shaded area is going to the left of 0 (this means x is negative):
x ≤ 0
Blue Line:
The shaded area is below the line, so:
y ≤ mx + b
When x = 0, y is -5.
y ≤ mx - 5
From each point, you go up 3 units, and to the right 4 units, so the slope is
.

The outlier is 68
The median is 102
First quartile: 87
Third Quartile: 115
The interquartile range is 87-115
Answer:
B) The scale on the y-axis could be changed to 25–40.
Answer:
you need to show or tell us the problem for us to be able to help you
Step-by-step explanation:
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