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faust18 [17]
3 years ago
6

Acid rain is: dust, soot, and other finely divided solid and liquid particles. a condition associated with smog that causes eye

irritation, irritation of the respiratory tract, and chest pains. a mixture of pollutants, principally ground-level ozone. an atmospheric condition during which a warm layer of air stalls above a cool layer. the precipitation of acidic compounds formed when components of air pollution interact with other components in the air.
Chemistry
1 answer:
anastassius [24]3 years ago
4 0

Answer:

The correct option is: the precipitation of acidic compounds formed when components of air pollution interact with other components in the air.

Explanation:

<u>Acid rain</u> is a form of precipitation which is usually <u>acidic in nature</u>. The acidic nature of rain is due to the reaction of <u>water molecules with sulfur dioxide, carbon dioxide and nitrogen oxide present in the air, to produce acids.</u>

There are many adverse effects of acid rain, some of them are: effect on water bodies, forests, living organisms, corrosion of structures made of steel and weathering of buildings.

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How many kilowatt-hours of energy are necessary to heat the air in the house from 9 ∘C to 27 ∘C? The heat capacity of air is 1.0
musickatia [10]

Answer:

The amount of air (in grams) is required for an answer. The process is outlined below.

Explanation:

An example for 1 kg of air:

Energy = (specific heat)*(mass)*(temperature change)

Joules = (1.03J/g°C)*(1,000g)*(27°C - 9°C)

Joules = 18540J

Coversion: 1 Joule = 2.78E-07 kwh

Kwh to heat 1 kg of air from 9 to 27°C is 5.15E-03 kwh

Use the same process with the actual mass of air in the house. If you are given house dimensions, calculate the volume and multiply by the density of air to get grams air. (Remember to subtract the volume taken up by household items (e.g., beer cans).

3 0
3 years ago
Radium has a half-life of 1,620 years. In how many years will a 1 kg sample of radium decay and reduce to 0.125 kg of radium?
Tasya [4]
We can calculate years by using the half-life equation. It is expressed as:

A = Ao e^-kt

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</span>From the half-life data, we can calculate for k.

1/2(Ao) = Ao e^-k(1620)
<span>k = 4.28 x 10^-4
</span>
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Explanation:

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Answer is #4 (neutrons)

Explanation:

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