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vovangra [49]
2 years ago
7

The oxidation of nitrogen monoxide is favored at 457 K:2NO(g) + O₂(g) ⇆ 2NO₂(g) Kp = 1.3 ˣ 10⁴(a) Calculate Kc at 457 K.

Chemistry
1 answer:
vesna_86 [32]2 years ago
7 0

Kc at 457 K is 4.88 × 10⁵.

<h3></h3><h3>What is Kc?</h3>

The ratio of the equilibrium concentrations of the products over the equilibrium concentrations of the reactants, each raised to the power of their respective stoichiometric coefficients, is known as the equilibrium constant, or Kc.

Kp = Kc(RT)∧Δn

Kp = 1.3 ˣ 10⁴

Δn = -1

Kc = 4.88 × 10⁵.

to learn more about Kc go to -

brainly.com/question/19340344

#SPJ4

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