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Rama09 [41]
3 years ago
13

What happens to elements when they gain energy

Chemistry
2 answers:
Lana71 [14]3 years ago
6 0
Electrons jump to higher orbits and the entire atom moves around more energetically
kati45 [8]3 years ago
4 0
They loose a valence electron
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In a lab, the mass of object A is 2.5 kg. Object A weighs:
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24.5 N hope it helps
4 0
3 years ago
Read 2 more answers
what is an empirical formulaWhat is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)?
Margarita [4]

Answer:

Percentage composition = 14.583%

Explanation:

In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.

Percentage composition by mass of Nitrogen

Nitrogen = 14g/mol

In one mole of the compound;

Mass of Nitrogen = 1 mol * 14g/mol = 14g

Mass of compound = 1 mol * 96.0 g/mol = 96

Percentage composition of Nitrogen = (Mass of Nitrogen /  Mass of compound) * 100

percentage composition = 14/96   * 100

Percentage composition = 0.14583 * 100

Percentage composition = 14.583%

3 0
3 years ago
How many liters of a 3 M NaOH stock solution would you need to make 552 mL of a 105 mM NaOH dilution
Ganezh [65]

Answer:

0.01932 L

Explanation:

First we <u>convert 105 mM to M</u>:

  • 105 mM / 1000 = 0.105 M

Next we <u>convert 552 mL to L</u>:

  • 552 mL / 1000 = 0.552 L

Then we use the following equation:

  • C₁V₁=C₂V₂

Where:

  • C₁ = 3 M
  • V₁ = ?
  • C₂ = 0.105 M
  • V₂ = 0.552 L

We<u> input the given data</u>:

  • 3 M * V₁ = 0.105 M * 0.552 L

And <u>solve for V₁</u>:

  • V₁ = 0.01932 L
7 0
3 years ago
A solution of NaCl ( aq ) is added slowly to a solution of lead nitrate, Pb ( NO 3 ) 2 ( aq ) , until no further precipitation o
statuscvo [17]

Answer : The molarity of Pb(NO_3)_2  solution is, 0.352 M

Explanation :

First we have to calculate the moles of PbCl_2

\text{Moles of }PbCl_2=\frac{\text{Given mass }PbCl_2}{\text{Molar mass }PbCl_2}

Molar mass of PbCl_2 = 278.1 g/mol

\text{Moles of }PbCl_2=\frac{19.58g}{278.1g/mol}=0.07041mol

Now we have to calculate the moles of CaCl_2

The balanced chemical equation is:

Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 1 mole of PbCl_2 produced from 1 mole of Pb(NO_3)_2

So, 0.07041 mole of PbCl_2 produced from 0.07041 mole of Pb(NO_3)_2

Now we have to calculate the molarity of Pb(NO_3)_2

\text{Molarity of }Pb(NO_3)_2=\frac{\text{Moles of }Pb(NO_3)_2}{\text{Volume of solution in (L)}}

\text{Molarity of }Pb(NO_3)_2=\frac{0.07041mol}{0.200L}=0.352M

Therefore, the molarity of Pb(NO_3)_2  solution is, 0.352 M

4 0
3 years ago
Every element has a unique amount of
tamaranim1 [39]
Protons is the answer
5 0
3 years ago
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