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3 years ago

What happens to elements when they gain energy

Chemistry

2 answers:

Lana71 [14]3 years ago

6 0

Electrons jump to higher orbits and the entire atom moves around more energetically

kati45 [8]3 years ago

4 0

They loose a valence electron

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In a lab, the mass of object A is 2.5 kg. Object A weighs:

zzz [600]

24.5 N hope it helps

4 0

3 years ago

Read 2 more answers

what is an empirical formulaWhat is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)?

Margarita [4]

Answer:

Percentage composition = 14.583%

Explanation:

In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.

Percentage composition by mass of Nitrogen

Nitrogen = 14g/mol

In one mole of the compound;

Mass of Nitrogen = 1 mol * 14g/mol = 14g

Mass of compound = 1 mol * 96.0 g/mol = 96

Percentage composition of Nitrogen = (Mass of Nitrogen / Mass of compound) * 100

percentage composition = 14/96 * 100

Percentage composition = 0.14583 * 100

Percentage composition = 14.583%

3 0

3 years ago

How many liters of a 3 M NaOH stock solution would you need to make 552 mL of a 105 mM NaOH dilution

Ganezh [65]

Answer:

0.01932 L

Explanation:

First we convert 105 mM to M:

105 mM / 1000 = 0.105 M

Next we convert 552 mL to L:

552 mL / 1000 = 0.552 L

Then we use the following equation:

C₁V₁=C₂V₂

Where:

C₁ = 3 M

V₁ = ?

C₂ = 0.105 M

V₂ = 0.552 L

We input the given data:

3 M * V₁ = 0.105 M * 0.552 L

And solve for V₁:

V₁ = 0.01932 L

7 0

3 years ago

A solution of NaCl ( aq ) is added slowly to a solution of lead nitrate, Pb ( NO 3 ) 2 ( aq ) , until no further precipitation o

statuscvo [17]

Answer : The molarity of $Pb(NO_3)_2$ solution is, 0.352 M

Explanation :

First we have to calculate the moles of $PbCl_2$

$\text{Moles of }PbCl_2=\frac{\text{Given mass }PbCl_2}{\text{Molar mass }PbCl_2}$

Molar mass of $PbCl_2$ = 278.1 g/mol

$\text{Moles of }PbCl_2=\frac{19.58g}{278.1g/mol}=0.07041mol$

Now we have to calculate the moles of $CaCl_2$

The balanced chemical equation is:

$Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)$

From the balanced reaction we conclude that

As, 1 mole of $PbCl_2$ produced from 1 mole of $Pb(NO_3)_2$

So, 0.07041 mole of $PbCl_2$ produced from 0.07041 mole of $Pb(NO_3)_2$

Now we have to calculate the molarity of $Pb(NO_3)_2$

$\text{Molarity of }Pb(NO_3)_2=\frac{\text{Moles of }Pb(NO_3)_2}{\text{Volume of solution in (L)}}$

$\text{Molarity of }Pb(NO_3)_2=\frac{0.07041mol}{0.200L}=0.352M$

Therefore, the molarity of $Pb(NO_3)_2$ solution is, 0.352 M

4 0

3 years ago

Every element has a unique amount of

tamaranim1 [39]

Protons is the answer

5 0

3 years ago