Answer:
Percentage composition = 14.583%
Explanation:
In chemistry, the emprical formular of a compound is the simplest formular a compound can have. It shows the simplest ratio in which the elements are combined in the compound.
Percentage composition by mass of Nitrogen
Nitrogen = 14g/mol
In one mole of the compound;
Mass of Nitrogen = 1 mol * 14g/mol = 14g
Mass of compound = 1 mol * 96.0 g/mol = 96
Percentage composition of Nitrogen = (Mass of Nitrogen / Mass of compound) * 100
percentage composition = 14/96 * 100
Percentage composition = 0.14583 * 100
Percentage composition = 14.583%
Answer:
0.01932 L
Explanation:
First we <u>convert 105 mM to M</u>:
Next we <u>convert 552 mL to L</u>:
Then we use the following equation:
Where:
We<u> input the given data</u>:
- 3 M * V₁ = 0.105 M * 0.552 L
And <u>solve for V₁</u>:
Answer : The molarity of
solution is, 0.352 M
Explanation :
First we have to calculate the moles of 

Molar mass of
= 278.1 g/mol

Now we have to calculate the moles of 
The balanced chemical equation is:

From the balanced reaction we conclude that
As, 1 mole of
produced from 1 mole of 
So, 0.07041 mole of
produced from 0.07041 mole of 
Now we have to calculate the molarity of 


Therefore, the molarity of
solution is, 0.352 M