True or false

A 4.5-liter sample of a gas has 0.80 mole of the gas. If 0.35 mole of the gas is added, what is the final volume of the gas? Tem

AVprozaik [17]

Answer:

6.5 liters will be your answer

Explanation:

5 0

3 years ago

Read 2 more answers

Equation balancing

meriva

Answer:

For a: The balanced equation is $2S(s)+3O_2(g)\rightarrow 2SO_3(g)$

For c: The balanced equation is $2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

Explanation:

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For (a):

The given unbalanced equation follows:

$S(s)+O_2(g)\rightarrow SO_3(g)$

To balance the equation, we must balance the atoms by adding 2 infront of both $S(s)$ and $SO_3$ and 3 in front of $O_2$

For the balanced chemical equation:

$2S(s)+3O_2(g)\rightarrow 2SO_3(g)$

For (b):

The given balanced equation follows:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)$

The given equation is already balanced.

For (c):

The given unbalanced equation follows:

$2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)$

To balance the equation, we must balance the atoms by adding 2 infront of $H_2O(l)$

For the balanced chemical equation:

$2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

For (d):

The given balanced equation follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

The given equation is already balanced.

4 0

3 years ago

Do hydrogen lose 1 2 or 3 electrons to other atoms

iren2701 [21]

Answer: Hydrogen can lose as much as possible there is no limits to it.

Hope this helps!

I am joyous to assist you anytime!

-Jarvis

Extras: Hydrogen is the chemical element with the symbol H and atomic number 1. hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe (;

7 0

3 years ago

When may a scientific theory be revised?

Anika [276]

Answer:

it can be revised at any time.

Explanation:

6 0

4 years ago

Read 2 more answers

Consider the balanced reaction

VARVARA [1.3K]

The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

<h3>What is the use of aluminium chloride ?</h3>

Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.

Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis

The balanced chemical equation represents the mole ratio in which the chemicals combine.

In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.

Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.

But this quantity of Al has a mass in grams of

m = n × Mr

= 8.70 mol × 27g/mol

= 234.9 g

Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

Learn more about mole concept here ;

https://brainly.in/question/12599804

#SPJ1

4 0

2 years ago