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Thepotemich [5.8K]
2 years ago
7

A solution of HCl has mc012-1.jpg = 0.01 M. What is the pH of this solution?

Chemistry
2 answers:
marin [14]2 years ago
8 0

Answer: The pH of the 0.02 M HCl solution is 2.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ion concentration in a solution.

pH=-\log[H^+]

The pH of the HCl solution of 0.01 Molar willbe :

HCl(aq)\rightarrow H^+(aq)+Cl^-(aq)

0.01 Molar of HCl will produce 0.01 M of [H^+] ions.

[H^+]=0.01 M

pH=-\log[H^+]=-\log[0.01]=2

The pH of the 0.02 M HCl solution is 2.

xxMikexx [17]2 years ago
4 0
PH = -log10 [H+]. So anwer 2 pH
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Which of the following is true for balancing equations?
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A.

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5 0
3 years ago
The pH of a solution can be calculated using which formula?
VikaD [51]

Answer:

The formula for calculating pH is pH=−log[H_3O+ ]

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PH= - log[H+ ]

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2 years ago
Calculate the maximum amount of useful work that can be obtained and comment on the spontaneity for the reaction at 25C :
harkovskaia [24]

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1.41 *10^{3}  kJ/mol

Explanation:

First, we find in the tables the ΔH of formation of each compound. As you can see in the (image 1)

Then we solve the ecuation for ΔH°reaction

ΔH°reaction=∑ΔH°f(products)−∑ΔH°f(Reactants)

ΔH°reaction= (-2* 393.5 - 2*285.8) - (52.4 + 0) kJ/mol

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3 0
3 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
2 years ago
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