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3 years ago

Match the subtraction expressions with their answers.

Mathematics

2 answers:

lyudmila [28]3 years ago

6 0

Answer:

1. (a² - b)/(a³b²)= 1/ab² - 1/a²b

2. (b - a)/a³b³ = 1/a³b² - 1/a²b³

3. (2 - ab²)/(a²b³) = 2/a²b³ - 1/ab

4. (2 - a)/a³b³ = 2/a³b³ - 1/a²b³

Step-by-step explanation:

To do this we'll break down fraction to least term through division.

The solution is as follows

1. (a² - b)/(a³b²)

Splitting the fraction;

a²/a³b² - b/a³b²

= 1/ab² - 1/a²b

2. (b - a)/a³b³

Splitting the fraction.

b/a³b³ - a/a³b³

1/a³b² - 1/a²b³

3. (2 - ab²)/(a²b³)

Splitting the fraction.

2/a²b³ - ab²/a²b³

2/a²b³ - 1/ab

4. (2 - a)/a³b³

Splitting the fraction

2/a³b³ - a/a³b³

2/a³b³ - 1/a²b³

alexira [117]3 years ago

5 0

Answer:

the order is

2,4,1,3

(the 1st answer is the 2nd option)

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Which statement best describes the solution to this system of equations?

kondaur [170]

Answer:

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Use factoring to simplify the expression x^2-x-6/x-3 assume that x does not equal 3

Gre4nikov [31]

This works out beautifully. You COULD use long division here, but since your numerator is a quadratic, your first instinct should be to try and factor it. If you factor it, it works out to be (x - 3)(x + 2). Now it just so happens that when you do that, the (x - 3) in the numerator will cancel with the (x - 3) in the denominator leaving you with one sad and lonely (x + 2) as your answer.

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2 years ago

How to solve X + y = 2<br> X - y = 4

SpyIntel [72]

So y+x=2
x-y=4
one way is subsituteion where yousubisutte one of the number for another exg

x-y=4
add y to both sides
x=y+4
subsitute y+4 for x in x+y=2
y+4+y=2
2y+4=2
subtract 4 from both sides
2y=-2
divide both sides by 2
y=-1
subsiutte
x+y=2
x-1=2
x=3

or elimination

x+y=2
x-y=4
add the two equations and cancel the y terms

x+x+y-y=2+4
2x=6
divide both sides by 2
x==3
subsitute
x+y=2
3+y=2
y=-1

so x=3
y=-1

5 0

3 years ago

Domain and range of the inequality y<√x+3 +1

Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

y < $\sqrt{x+3}+1$

Related equation:

y = $\sqrt{x+3}+1$

The equation defined as,

x+3 > 0

x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3} \geq 0$