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Answer:
V_f = 287.04 mL
Explanation:
We are given the initial/original volume of the glycerine as 285 mL.
Now, after it is finally cooled back to 20.0 °C , its volume is given by the formula;
V_f = V_i (1 + βΔT)
Where;
V_f is the final volume
V_i is the original volume = 285 mL
β is the coefficient of expansion of glycerine and from online tables, it has a value of 5.97 × 10^(-4) °C^(−1)
Δt is change in temperature = final temperature - initial temperature = 32 - 20 = 12 °C
Thus, plugging in relevant values;
V_f = 285(1 + (5.97 × 10^(-4) × 12))
V_f = 287.04 mL
The circular but relatively flat portion of the galaxy is the Disk
Answer:
By turning the vehicle "ON" position you can check to see if the gauges light works.
When we switch ON or turn a key to ON the engine, we can find all the gauges working or not.
1) Upward motion
y1 = Vo*t - g(t^2) / 2
2) Downward motion
y2 = D - [Vo*t + g(t^2) / 2]
3) Collision => y1 = y2
y1 = Vo*t - g(t^2) / 2
y2 = D - [Vo*t + g(t^2) / 2]
Vo*t - g(t^2) / 2 = D - [Vo*t + g(t^2) / 2]
Vo*t - g(t^2) / 2 = D - Vo*t - g(t^2)/2
D = 2Vo*t => t = D / (2Vo)
Substitute the value of t in the equation of y1 (it is the same if you do it in the equation of y2)
y1 = Vo*t - g(t^2) / 2 = Vo [D/(2Vo) ] - g [D / (2Vo)]^2 / 2
y1 = D/2 - g(D^2) / 8(Vo ^2)
Answer: y1 = D/2 - g(D^2) / 8(Vo ^2)