Calculate the pressure when a force of 200N acts on an area of 0.05cm2 .
1 answer:
You might be interested in
Answer:
a) The initial total mechanical energy of the projectile is 498556.296 joules.
b) The work done on the projectile by air friction is 125960.4 joules.
c) The speed of the projectile immediately before it hits the ground is approximately 82.475 meters per second.
Explanation:
a) The system Earth-projectile is represented by the Principle of Energy Conservation, the initial total mechanical energy () of the project is equal to the sum of gravitational potential energy (
) and translational kinetic energy (
), all measured in joules:
(Eq. 1)
We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:
(Eq. 1b)
Where:
- Mass of the projectile, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
- Initial height of the projectile above ground, measured in meters.
- Initial speed of the projectile, measured in meters per second.
If we know that ,
,
and
, the initial mechanical energy of the earth-projectile system is:
The initial total mechanical energy of the projectile is 498556.296 joules.
b) According to this statement, air friction diminishes the total mechanical energy of the projectile by the Work-Energy Theorem. That is:
(Eq. 2)
Where:
- Initial total mechanical energy, measured in joules.
- FInal total mechanical energy, measured in joules.
- Work losses due to air friction, measured in joules.
We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:
(Eq. 2b)
Where:
- Mass of the projectile, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
- Maximum height of the projectile above ground, measured in meters.
- Current speed of the projectile, measured in meters per second.
If we know that ,
,
,
and
, the work losses due to air friction are:
The work done on the projectile by air friction is 125960.4 joules.
c) From the Principle of Energy Conservation and Work-Energy Theorem, we construct the following model to calculate speed of the projectile before it hits the ground:
(Eq. 3)
Where:
- Total mechanical energy of the projectile at maximum height, measured in joules.
- Potential gravitational energy of the projectile, measured in joules.
- Kinetic energy of the projectile, measured in joules.
- Work losses due to air friction during the upward movement, measured in joules.
We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:
(Eq. 3b)
If we know that ,
,
,
and
, the final speed of the projectile is:
The speed of the projectile immediately before it hits the ground is approximately 82.475 meters per second.