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Assoli18 [71]
3 years ago
12

13) Can two nonzero perpendicular vectors be added together so their sum is zero? Explain.

Physics
2 answers:
statuscvo [17]3 years ago
4 0

Answer:

sum of two perpendicular nonzero vectors can not be ZERO

Explanation:

As we know by the sum or addition of two vectors is given by

R = \sqrt{a^2 + b^2 + 2abcos\theta}

here we know that

a and b are the magnitude of two vectors

\theta = angle between two vectors

so as we know that here two vectors are perpendicular to each other

so we will have

R = \sqrt{a^2 + b^2}

now since the is sum of two positive non zero numbers so it can not be zero

so sum of two perpendicular nonzero vectors can not be ZERO

Neporo4naja [7]3 years ago
3 0

In order for two vectors to add to zero, they must have the same magnitude and point in opposite directions.

Two perpendicular vectors, by definition, make a right angle with each other whereas two vectors pointing in opposite directions form a straight line.

Because of this, two perpendicular vectors with nonzero magnitudes will never add to zero.

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A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t
Archy [21]

Answer:

A=81mm^2

Explanation:

We know that for a capacitor Q=CV, where <em>Q </em>is the charge of one plate, <em>C</em> the capacitance and <em>V</em> the potential between the plates.

We also know that Q=\sigma A, since \sigma is the surface charge density and <em>A</em> the area of the plate (both equal in our case).

Putting all together:

A=\frac{CV}{\sigma}

Which for our values is:

A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that mm^2 is enough to describe an area).

8 0
3 years ago
The two hot-air balloons in the drawing are 48.2 and 61.0 m above the ground. A person in the left balloon observes that the rig
Lynna [10]

Answer:

x = 54.15 meters between the balloons horizontally.

Explanation:

Hence, vertical distance between balloons is 12.8 meters.

y= 61-48.2  = 12.2 m

A right-angle triangle is formed with,

angle θ = 13.3 degrees

opposite (y) = 12.8

adjacent (x) = ?

tan\theta = \dfrac{y}{x}

Now by putting the values in the above equation.

tan13^{\circ}=\dfrac{12.8}{x}

x=\dfrac{12.8}{tan13^{\circ}}

x = 54.15 meters between the balloons horizontally.

8 0
3 years ago
What's manifestation​
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2 years ago
Read 2 more answers
At an accident scene on a level road, investigators measure a car's skid mark to be 98 m long. It was a rainy day and the coeffi
shutvik [7]

Answer:

The speed of the car was 28 m/s.

Explanation:

Hi there!

The initial kinetic energy of the car, KE, is equal to the negative work, W, done by friction to bring the car to stop. Let´s write the work-energy theorem:

W = ΔKE = final kinetic energy - initial kinetic energy

In this case, the final kinetic energy is zero, then:

W = - initial kinetic energy

Since the work done by friction is negative (the work is done in opposite direction to the movement of the car), then:

Wfr = initial kinetic energy

The work done by friction is calculated as follows:

Wfr = Fr · d

Where:

Fr = friction force.

d = distance.

The friction force is calculated as follows:

Fr = N · μ

Where:

N = normal force.

μ = coefficient of friction

Since the only vertical forces acting on the car are the weight of the car and the normal force, and the car is not being accelerated in the vertical direction, the normal force has to be equal to the weight of the car (with opposite sign).

Then the friction force can be written as follows:

Fr = m · g · μ

Where:

m = mass of the car.

g =  acceleration due to gravity (9.8 m/s²)

The work done by friction will be:

W = m · g · μ · d

The equation of kinetic energy is the following:

KE =  1/2 · m · v²

Where

m = mass of the car.

v = speed.

Then:

W = KE

m · g · μ · d = 1/2 · m · v²

2 · g · μ · d = v²

2 · 9.8 m/s² · 0.40 · 98 m = v²

v = 28 m/s

The speed of the car was 28 m/s.

7 0
4 years ago
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