Motion of a dog is shown in this velocity vs time graph.
1 answer:
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Answer:
b) the potential difference across each is the same.
Explanation:
When resistors are connected in parallel with each other
then the terminals of all the resistors will connected across the terminals of the battery
So we know the potential difference of the battery is same across all the resistors
So we can say that the equivalent resistance of all the resistance is
so its not the mean of all resistors
also we know that the resistance are all different so power across each resistance is different given as
also current in each resistance is also different and given by
so correct answer will be
b) the potential difference across each is the same.
Answer:
A 8.0 cm diameter horizontal pipe gradually narrows to 5.0 cm. The the water flows through this pipe at certain rate, the gauge pressure in these two sections is 31.0 kPa and 24.0 kPa, respectively. What is the volume of rate of flow?
The flow rate is 3.1175×10⁻³ m³/s
Explanation:
To solve the question we rely on Bernoulli's principle as follows
thus where the pipe is horizontal we have
z₁ = z₂ hence the above equattion becomes
since the flow rate is constant then
Q = v₁A₁ = v₂A₂
Where is the area of the two sections given by A₁ = π·D₁²÷4 and
A₂ = π·D₂²÷4
Thereffore A₁ = π·0.08²÷4 = 5.02×10⁻³ m²
and A₂ = π·0.05²÷4 = 1.96×10⁻³ m²
v₁ = v₂A₂/A₁ =0.391×v₂
The given pressures are P₁ = 31.0 kPa and P₂ = 24.0 pKa and
ρ = 1000 kg/m³
Plugging the values into the above equation we get
31.0 kPa +0.5× 1000 kg/m³× (0.391×v₂)² = 24.0 pKa +0.5×1000 kg/m³×v₂²
= 31000+76.3·v₂² =24000+500·v₂²
or 423.706·v₂² = 7000
v₂² = 7000/423.706 = 16.52 or v₂ = 4.065 m/s and v₁ 0.391×4.065 = 1.59 m/s
The flow rate = v₂A₂ = 1.59×1.96×10⁻³ = 3.1175×10⁻³ m³/s