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3 years ago

Solve the inequality. Graph the solution. c9≤−4

Mathematics

1 answer:

Dima020 [189]3 years ago

6 0

Solving the inequality $c9\leq -4$ we get $c\leq \frac{-4}{9}$

The graph is shown in figure attached below.

Step-by-step explanation:

We need to solve the inequality $c9\leq -4$ and graph the solution.

Solving:

$c9\leq -4$

Divide both sides by 9

$c\leq \frac{-4}{9}$

$c\leq -0.44$

The graph is shown in figure attached below.

So, solving the inequality $c9\leq -4$ we get $c\leq \frac{-4}{9}$

Keywords: Graph the inequality

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Answer:

x =(22-√196)/6=(11-7)/3= 1.333

Step-by-step explanation:

(3x2 - 22x) + 24 = 0

The first term is, 3x2 its coefficient is 3 .

The middle term is, -22x its coefficient is -22 .

The last term, "the constant", is +24

Step-1 : Multiply the coefficient of the first term by the constant 3 • 24 = 72

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Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -18 and -4

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Step-4 : Add up the first 2 terms, pulling out like factors :

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Add up the last 2 terms, pulling out common factors :

4 • (x-6)

Step-5 : Add up the four terms of step 4 :

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Which is the desired factorization

Equation at the end of step 2:

(x - 6) • (3x - 4) = 0

STEP 3:

Theory - Roots of a product

3.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

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Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t

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Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 450, \sigma = 100$