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mafiozo [28]
3 years ago
13

The standard form of the equation of a circle with center (h, k) and radius r is __________________.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}
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The area of circle can be expressed by the
nadezda [96]

9514 1404 393

Answer:

  r = √(A/π)

Step-by-step explanation:

Solve for r. Do this by dividing by the coefficient of the r² term, then taking the square root.

  A = πr²

  A/π = r²

  r = √(A/π)

5 0
3 years ago
How many complex roots does the equation below have? X^6+x^3+1=0
gladu [14]
If you find the discriminant it will tell you the number and types of roots. The discriminant is the value b^2 -4ac.
a = 1
b = 1
c = 1
1^2 - 4*1*1
1-4 = -3
Since this is a negative number there will be 2 complex roots.
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3 years ago
Read 2 more answers
X^2+2x+5=0 solve for X
Oksana_A [137]
Is it no real solutions?
7 0
3 years ago
Rhian sat a maths test and an English test In the Maths test she scored 14 out of 17 In the English test she scored 31 out of 39
BabaBlast [244]

Answer:

Rhian did better in the Math test.  

Step-by-step explanation:

Given: Rhian scored 14 out of 17 in a Math test. In the English test she scored 31 out of 39.

To find: In which test did she do better?

Solution:

We have,

Rhian scored 14 out of 17 in a Math test.

Rhian scored 31 out of 39 in an English test.

So, first we need to find the percentage of the marks scored.

Percentage in the Math test =\frac{14}{17}\times100=82.35 \%.

Percentage in the English test =\frac{31}{39}\times100= 79.49\%.    

Clearly, the percentage in the Math test is greater than the percentage in the English test.

So, Rhian did better in the Math test.    

8 0
3 years ago
Amber, Bernie, and Carlos are working on a problem together. Their goal is to correctly apply the difference of cubes formula to
NeX [460]

Answer: Carlos is correct

Step-by-step explanation:

2x^5-250x^2

The first step is to factorize out 2x^2

2x^2(x^3-125)

This can be rewritten as

2x^2(x^3-5^3),

Recall, difference if cube (a^3-b^3)

= (a-b)(a^2 +ab + b^2)

from our equation,

a= x

b = 5.

So the difference of cubes will be

2x^2[(x-5) (x^2 + 5x + 5^2)]

=2x^2[(x-5) (x^2 + 5x + 25)]

Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.

Amber is incorrect because 125 is equal to b3, not b.

Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.

6 0
3 years ago
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