Answer:
<h2>d. $250</h2>
Step-by-step explanation:
We can use the equation of a straight line to model the cost of servicing the car.
let the cost be y and the number of hours be x
and the charge per hour is m
y=mx+c
y=50x+25
given that the time is 3.45 hours it is assumed that the charge is for 4 hours since for a fraction of 0.45 hours we are charged $50
y=50(4)+25
y=200+25
y=$225
Answer:
210
Step-by-step explanation:
Rewriting input as fractions if necessary:
4/7, 5/14, 4/15
For the denominators (7, 14, 15) the least common multiple (LCM) is 210.
LCM(7, 14, 15)
Therefore, the least common denominator (LCD) is 210.
Calculations to rewrite the original inputs as equivalent fractions with the LCD:
4/7 = 4/7 × 30/30 = 120/210
5/14 = 5/14 × 15/15 = 75/210
4/15 = 4/15 × 14/14 = 56/210
Answer:
16-4x^2
Step-by-step explanation:
u start multiplying them by each other .
4×4= 16
4×2x= 8x
-2x×4= -8x
-2x×2x= -4x^2
now u combine like terms
8x+-8x = 0
16-4x^2
I hope u understood.... lol
Answer:
Step-by-step explanation:
m=x^3+y^2-6(x-y)-2021
distribute: 6x-6y
now you have m=x^3 + y^2 - 6x - 6y - 2021
Answer:
And for this case the margin of error would be:
If the level of confidence increase we can conclude that the value of 
would increase and the the confidence interval would be wider, since the margin of error increase.
c. Increase; wider
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
Let's assume that we have a parameter of interest 
and we want to estimate the value of p with 
and in general the confidence interval if the distribution of p is normal is given by:
And for this case the margin of error would be:
If the level of confidence increase we can conclude that the value of would increase and the the confidence interval would be wider, since the margin of error increase.
c. Increase; wider
