I believe it is D. Hope this helps!
It would be to little because it would only be 30 cents
Answer:
PQ and QR are congruent.
Step-by-step explanation:
The length of PQ = sqrt [(2 - -1)^2 + (-1 - 3)^2]
= sqrt 25
= 5 units.
QR = sqrt [(5-2)^2 + (3 - -1)^2) ]
= sqrt 25
= 5 units.
PR = sqrt [ ( 3-3^2 + (5- -1)^2]
= sqrt 36
= 6 units.
Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
brainly.com/question/1942755
#SPJ4
Sqrt(8^2 + 3^2)
Y is 3,4
Z is -5,1
3-(-5) = 8 (difference between x coords)
4-1 = 3 (difference between y coords)
Equation is: sqrt( (xdiff)^2 + (ydiff)^2 )
