Answer:
1.45 *10^23 atoms C
Explanation:
3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane
in 1 mol C4H10 -------- 4 mol C
in 0.06024 mol C4H10 -------- 4*0.6024 = 0.241 mol C
0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C
The answer is: Dividing the number of molecules in the sample by Avogadro's number.
The Avogadro’s number is the number of atoms in 12 grams of the isotope carbon-12 (¹²C).
Na is Avogadro number or Avogadro constant (the number of particles, in this example carbon, that are contained in the amount of substance given by one mole).
The Avogadro number has value 6.022·10²³ 1/mol in the International System of Units; Na = 6.022·10²³ 1/mol.
For example:
N(Ba) = 2.62·10²³; number of atoms of barium.
n(Ba) = N(Ba) ÷ Na.
n(Ba) = 1.3·10²⁴ ÷ 6.022·10²³ 1/mol.
n(Ba) = 2.158 mol; amount of substance of barium.
Answer:
16.8dm3
Explanation:
2 moles of CO gives 1 mole of N2
2 moles of CO= 2* 28= 56g
1 mole of N2 = 1* 22.4dm
56g of CO gives 22.4dm3 of N2
42.7 of CO will give> (42.7*22.4)/56
=16.8dm3
Answer : The correct answer is 2.36 mol of gold
1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).
So the formula relating mole and number of atoms is given as :
Plugging value in formula :
Mole of gold = 2.36 mol
Answer:
0.074
Explanation:
15% means that in 100 g of solution 15 g sodium hydroxide is present.
Mass of water = 100 - 15 = 85 g
Number of moles of sodium hydroxide:
Number of moles = 15 g/40 g/mol
Number of moles = 0.375 mol
Number of moles of water:
Number of moles = 85 g/18 g/mol
Number of moles = 4.7 mol
Moles fraction of NaOH:
moles of NaOH/ moles of solvent + moles of solute
0.375 mol/ 0.375 mol+4.7mol
0.375 mol / 5.075 mol
0.074
