Carbon can be used in fuel
Answer: The mass of silver is 1.19 X 10^14 M g
Explanation: The volume of the truck is 402 cubic feet or 1.138 x 10⁷ mm.
The density of silver is 10.49 g/mL.
We need to find the mass of silver that will fit in this moving truck. Density equals mass divided by volume. So,
<h2>
d= m/v where m= mass m= d x V</h2><h2>
M=10.49 g/mL X 1.138 X 10∧7 mL</h2>
M=119376200 g 1 gram=10⁻⁶ Megagram 119376200= 1.19 X 10^14 Mg hence the mass of silver is 1.19 X 10^14 M g hopefully this will help you please mark me as brainlist
Answer : The equilibrium concentration of CO in the reaction is, 
Explanation :
The given chemical reaction is:

The expression for equilibrium constant is:
![K_c=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
As we are given:
Concentration of
at equilibrium = Concentration of 
So,
![K_c=\frac{[Cl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
![K_c=\frac{1}{[CO]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B1%7D%7B%5BCO%5D%7D)
![1.2\times 10^3=\frac{1}{[CO]}](https://tex.z-dn.net/?f=1.2%5Ctimes%2010%5E3%3D%5Cfrac%7B1%7D%7B%5BCO%5D%7D)
![[CO]=8.3\times 10^{-4}M](https://tex.z-dn.net/?f=%5BCO%5D%3D8.3%5Ctimes%2010%5E%7B-4%7DM)
Therefore, the equilibrium concentration of CO in the reaction is, 
I did the math and i got 450 but i dont know if its right