Answer:
V = 0.63 L
Explanation:
To solve this problem, we need to use the Charle's law which is a law that involves temperature and volume, assuming we have a constant pressure. The problem do not state that the pressure is being altered, so we can safely assume that the pressure is constant (Maybe 1 atm).
Now, as the pressure is constant, the Charle's law is the following:
V₁ / T₁ = V₂ / T₂ (1) V is volume in Liter, and T is temperature in Kelvin.
Using this law with the given data, we solve for V₂:
V₂ = V₁T₂ / T₁
Before we use this expression, let's convert the temperatures to Kelvin:
T₁ = 19 + 273 = 292 K
T₂ = 250 + 273 = 523 K
Now, let's calculate the volume of the balloon:
V₂ = 0.35 * 523 / 292
<h2>
V₂ = 0.63 L</h2>
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I couldn't find the answer to your question.
Your answer is x= 1/2, this is because to get the x alone you need to move the 2 so you divide 2x by to and you have to do the same to the other side so 1/2, and you get x=1/2
It is important to note that mass and mole pertain to different units of measurement, thus, 1 mole of one substance may have a lower or higher mass compared to a different substance. The mass of an object gives a measure of the number of atoms present in the substance while the number of moles of a substance refers to the amount of a chemical substance it has and is often used for chemical reactions.
For this problem, we first get the molar mass of each substance:
Molar mass of H2O = 18.0153 g/mol
Molar mass of C6H12O6 = 180.1559 g/mol
We then convert each substance into units of mass (grams), where:
1 mol H20 x 18.0153 g/mol = 18.0153 g H20
1 mol C6H12O6 x 180.1559 g/mol = 180.1559 g C6H12O6
It was then determined that 1 mole of glucose has more mass than 1 mole of water.
The answer is 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
<h3>
What is Molarity ?</h3>
Molarity is defined as the amount of solute (in moles)in per litre of solution.
It is also known as molar concentration of a solution , It is expressed in mol/l
We can rearrange this equation to get the number of moles:
n= M * V
The molarity of solution is 8.3 M and the volume given is 4 litres
the moles will be n = 8.30 * 4 = 33.2 moles
Therefore 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
To know more about molarity
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