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Rzqust [24]
3 years ago
10

How many moles of gold are there in 14.2×1023 atoms of gold?

Chemistry
2 answers:
timofeeve [1]3 years ago
4 0

Answer : The correct answer is 2.36 mol of gold

1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).

So the formula relating mole and number of atoms is given as :

Mole = \frac{given number of atom }{ 6.022 * 10^2^3 atom}    * 1 mol

Plugging value in formula :

Mole = \frac{14.2 *10^2^3 }{6.022 x10^2^3}   * 1 mol

Mole of gold = 2.36 mol

kifflom [539]3 years ago
4 0
You would use mole constant which is 6.02x10^23 so your answer would be 14.2x10^23/mole constant 
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Which of these phrases accurately describe disproportionation? Check all that apply.
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A single compound is simultaneously oxidized and reduced.

Explanation:

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Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

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Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

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To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

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pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

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The pH of the solution after adding 0.150 moles of solid LiF is 3.84

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Answer:

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