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olga nikolaevna [1]

3 years ago

12

Which of the following presidential candidates was nominated by self-announcement?

1 answer:

MAXImum [283]3 years ago

8 0

It was former President Woodrow Wilson who was nominated by self-announcement and he become the president of the United States of America in the year 1913 up to the year 1921. He was the 28th president of the United States and he runs on the presidential election year 1912 and won the presidential title. He served the country for 9 years. Former President Woodrow Wilson was born is Virginia, US in 1856 and he died on the year 1924 at the age of 67.

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Fission and Fusion of Atomic Nuclei:

bogdanovich [222]

Answer:

C B A D

Explanation:

6 0

3 years ago

Chlorofluorocarbons (CFCs) are no longer used as refrigerants because they destroy the ozone layer. Trichlorofluoromethane (CCl₃

Daniel [21]

Answer:

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

Explanation:

Entropy :It is defined as amount of energy which is unable to do work or the measurement of randomness or disorderedness in a system.

$S=\frac{Q}{T(Kelvins)}$

Molar heat of molar vaporization of Trichlorofluoromethane = 24.8 kJ/mol

Temperature at which Trichlorofluoromethan boils , T= 296.95 K

The molar entropy of the evaporation of Trichlorofluoromethan :

$=\frac{24.8 kJ/mol}{296.95 K}=0.083516 kJ/mol K = 83.516 J/molK$

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

8 0

3 years ago

How many atoms of potassium and how

Varvara68 [4.7K]

KOH? 6.022 x 10^23 atoms of potassium(K) are in one mole of KOH

8 0

3 years ago

Which of the following are excited in ultraviolet photoelectron spectroscopy?

zavuch27 [327]

Answer:

D. Valance Electrons

Explanation:

6 0

3 years ago

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

LenKa [72]

The average speed is calculated using the following formula $speed = \sqrt{\frac{3kT}{m} }$

Where

$k = 1.381 X 10^{-23} J / K$

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = $\frac{32}{6.023 X 10^{23} }$

mass of one molecule of oxygen will be = $5.31 X 10^{-23} g = 5.31 X 10^{-26} kg$

putting values

average speed = $\sqrt{\frac{3 X 1.381 X 10^{-23} X 298}{5.31 X 10^{-26} kg} }$

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0

3 years ago

Read 2 more answers