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olga nikolaevna [1]
3 years ago
12

Which of the following presidential candidates was nominated by self-announcement?

Chemistry
1 answer:
MAXImum [283]3 years ago
8 0
It was former President Woodrow Wilson who was nominated by self-announcement and he become the president of the United States of America in the year 1913 up to the year 1921. He was the 28th president of the United States and he runs on the presidential election year 1912 and won the presidential title. He served the country for 9 years. Former President Woodrow Wilson was born is Virginia, US in 1856 and he died on the year 1924 at the age of 67.
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Which of the following elements is the most reactive?<br> A. Ba<br> B. Cs<br> C. Hf<br> D. Lu
hodyreva [135]

Answer: Cs because its further to the right on the table, meaning its more reactive.

Explanation:

8 0
3 years ago
Which compound contains a triple bond?
Igoryamba
There are many compounds which contain triple bonds between two atoms. Few of the are as follow,

Nitrogen Molecule:

                           N₂   or   :N≡N:

Cyanide Ion:

                          CN⁻   or    [:C≡N:]⁻

Alkynes:
                          R-C≡C-R

Carbon Monoxide:

                          CO    or    :C≡O:

Among given compounds Alkynes belong to a class of unsaturated hydrocarbons. The carbon atom in alkyne is sp hybridized. These unsaturated hydrocarbons have their own characteristic chemical properties. 
6 0
3 years ago
Read 2 more answers
Help! I don't have the things to do this and its due TODAY! Could someone help me?
vodomira [7]

Answer:

--- The hot air inside the bottle creates an expansion and when the hot water is applied a contraction occurs, thus causing the balloon to be sucked.

--- An internal pressure is produced, joining the heat begins to decrease. As a consequence, the air molecule causes the balloon to enter the bottle thanks to the effect of the external pressure.

Explanation:

I hope I have helped with something.

4 0
3 years ago
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How many grams are in 4.65 mol of AI(NO2)3
nirvana33 [79]
To find out how many grams are in 4.65 moles of Al(NO₂)₃
Find out what the molar mass of Al(NO₂)₃ is
Al = 26.98 g/mol Al
N = 14 g/mol N
O = 16 g/mol O
Next, you have to look at the subscripts and figure out which they belong to, in this case:
Al = 26.98 g/mol Al
N₃ = 42 g/mol N₃
O₆ = 96 g/mol O₆
Finally, add the numbers together, so:
26.98 g/mol Al + 42 g/mol N₃ + 96 g/mol O₆ = 
164.98 g/mol Al(NO₂)₃
Now, you have 4.65 mol Al(NO₂)₃ so
164.98 g/mol Al(NO₂)₃ × 4.65 mol Al(NO₂)₃ =
767.157 grams of Al(NO₂)₃

6 0
3 years ago
What is the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml?
Firdavs [7]

Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock CuSO_4 solution = 2.5 M

V_1 = volume of stock CuSO_4solution = 5 ml  

M_1 = molarity of diluted CuSO_4 solution = ?

V_1 = volume of diluted CuSO_4 solution = 750 ml

Putting in the values we get:

2.5\times 5=M_2\times 750

M_2=0.017

Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

6 0
3 years ago
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