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Elena L [17]
4 years ago
5

25 POINTS HOW MUCH I NEED HELP PLEASE IM BEGGINGGG

Mathematics
1 answer:
Ghella [55]4 years ago
8 0

Answer:

<h2>x = -3</h2>

Step-by-step explanation:

It's a vertical line. Regardless of what point you go to on the line, it always has a value of -3 because it is going vertically (up and down) at -3.

Therefore the equation of a line is x = -3

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PLEASE Solve y=-2.4x+8.2
frez [133]

x =  -  \frac{41}{12}  + y \times  \frac{5}{12}

Step-by-step explanation:

y = 2.4x + 8.2

  • move 2.4x to the left-hand side and change its sign.
  • move y to the right-hand side and change its sign.

- 2.4x = 8.2 - y

  • Divide both sides of the equation by -2.4

\answer

  • x =  -  \frac{41}{12}  + y \times  \frac{5}{12}

<u>#CarryOnLearning</u>

3 0
3 years ago
Read 2 more answers
What is the equation for a line that passes through the points (-5,-4) and (10,14)?
Vinvika [58]

Answer:

y=6/5x+2

Step-by-step explanation:

1.find the slope(m)

m=y2-y1/x2-x1

m=14-(-4)/10-(-5)

m=14+4/10+5

m=18/15

m=6/5

y-y1=m(x-x1)

y-(-4)=6/5(x-(-5))

y+4=6/5(x+5)

y+4=6/5x+30/5

y=6/5x+30/5-4

y=6/5x+10/5

y=6/5x+2

6 0
3 years ago
A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco
bekas [8.4K]

answer:

f(t) = -9.9788169(t -0.76)^2 +57

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the  number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is f(x)= a(x-p)^2 +q  , where (p,q) is the turning point. now we substitute the turning point

f(t) = a(t-0.76)^2 + 57, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.

0 = a(3.15 - 0.76)^2 + 57

-57 =a(2.39)^2  

-57 = a(5.7121)

-57/5.7121 =a

-9.9788169 = a      then we substitute a to get the quadratic equation therefore f is

f(t) = -9.9788169(t-0.76)^2 +57

4 0
3 years ago
The sum of three consecutive odd integers is 57. what are the three integers
asambeis [7]

Answer:

17,19,21

Step-by-step explanation:

let the first odd number be "x"

formular : (x)+(x+2)+(x+4).

3x+6=57

3x=57-6

3x=51

x=51/3

x=17

apply the formular.

17,(17+2),(17+4)

17,19,21.

6 0
3 years ago
What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
4 years ago
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