Another way to write the expression the answer is this (t.14)-(t.5)
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
the answer is B 37 your welcome
Answer:
0
Step-by-step explanation:
The slope of the line is 0 as it is parallel to x-axis.
Slope = (y2 - y1)/(x2 - x1)
= (2-2)/(4-(-2))
= 0
Answer:
x = 
Step-by-step explanation:
x^2 + 8^2 = 9
Simplify the 8^2
x^2 + 64 = 9
Subtract 64 from both sides
x^2 = -55
Take the square root from both sides
x = +/- 
Simplify
x =
Hope this helps!
