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3 years ago

5

the length of a rectangle is 6 meters more than it's width of the the area of the rectangle is 135 square meters find it's demen

sion

1 answer:

bekas [8.4K]3 years ago

8 0

Answer:

The length is 15 meters and the width is 9 meters.

Explanation:

If we set this up as an algebraic equation, the length, l, and the width, w, would be set up as <span>l=w+6</span>

Provided <span>A=l⋅w</span>, we can substitute l as <span>w+6</span> so that <span>A=<span>(w+6)</span>⋅w=<span>w2</span>+6w</span>

If your Area, A is <span>135<span>m2</span></span>. we plug it in so that <span>135=<span>w2</span>+6w</span>

Subtract 135 from both sides to get <span>0=<span>w2</span>+6w−135</span>. If we factor this we get <span><span>(w+15)</span><span>(w−9)</span>=0</span>, so <span>w=−15or9</span>. Since distance can't be negative, <span>w=9</span>

If <span>l=w+6</span>, <span>l=9+6=15</span>

So the width is 9 meters and the length is 15 meters.

Hope it helps!

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To find y-intercept which is the point where the line touches the y-axis, we would plugin $x=0$ in the equation as the x-coordinate is 0 at y-axis.

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