$\bf sin(x)[csc(x)-sin(x)]~~=~~cos^2(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)\left[\cfrac{1}{sin(x)}-\cfrac{sin(x)}{1} \right]\implies \underline{sin(x)}\left[\cfrac{1-sin^2(x)}{\underline{sin(x)}} \right] \\\\\\ 1-sin^2(x)\implies cos^2(x)$

recall again, sin²(θ) + cos²(θ) = 1.

3 0

3 years ago

Identify the underlined place in 83.5851. Then round the number to that place. The 8 to the right is underlined.

Marina86 [1]

We have to round the number 83.5851 to the nearest hundredth.
If the next smallest place is greater than or equal to 5 we increase the value of the digit we are rounding to by one.
83.5851 ≈ 83.59
Answer: 83.59

8 0

3 years ago

Read 2 more answers

You roll two dice. What is the probability that the average of the high and low roll is exactly 3, to four decimal places?

Sladkaya [172]

Answer:

0.1111

Step-by-step explanation:

Given that you roll two dice.

the average of the high and low roll is exactly 3,

Since die can show only 1 to 6 we can say average can be 3 in each of the following case.

(1,5) (2,4) (3,3) (4,2) (5,1)

There cannot be any other combination to get average of 3.

Thus favourable events = 4

Sample space will have

(1,1)...(1,6)

(2,1)....

(6,1)...(6,6) i.e. 36

So probability that the average of the high and low roll is exactly 3

= $\frac{4}{36} \\=0.1111$

8 0

3 years ago

The area of the rectangle is 5 times the triangle

nirvana33 [79]

Don't know what you mean

8 0

3 years ago