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4 years ago

Pythagoras question please help

Mathematics

1 answer:

irinina [24]4 years ago

3 0

The Pythagorean theorem formula is a² + b² = c²

5² + 3² = 7²
25 + 9 = 49
25 + 9 = 34

So since it is not the same it is not a right triangle.

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EB bisects ∠RED. Find the measure of ∠BED if ∠REB = 5x – 3 and ∠RED = 8x + 16<br><br>plzzzzzzzzzzz

Allushta [10]

Answer:

this is 52 degrees

Step-by-step explanation:

7 0

3 years ago

Find an antiderivative F(x) with F′(x) = f(x) = 6 + 24x^3 + 18x^5 and F(1)=0.

7nadin3 [17]

Answer:

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

Step-by-step explanation:

Antiderivative F(x)

This is the integral of $F^{\prime}(x)$

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

$F(x) = \int (6 + 24x^3 + 18x^5) dx$

$F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K$

$F(x) = 6x + 6x^4 + 3x^6 + K$

F(1)=0

$F(X) = 0$ when $x = 1$ . We use this to find K.

$F(x) = 6x + 6x^4 + 3x^6 + K$

$0 = 6 + 6 + 3 + K$

$K = -15$

Thus

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

7 0

3 years ago

Cassidy wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is parallel to y = 5 x + 4 and that

Kryger [21]

Answer:

b=−5x+y

Step-by-step explanation:

Let's solve for b.

y=5x+b

Step 1: Flip the equation.

b+5x=y

Step 2: Add -5x to both sides.

b+5x+−5x=y+−5x

b=−5x+y

3 0

3 years ago

You work 4 hours on Monday, 4.5 hours on Tuesday, 7.25 hours on Thursday, and 12 hours on Saturday. If you get paid $11.52 per h

____ [38]

Answer:

$181.44

Step-by-step explanation:

First, you convert the hours worked to minutes <em>(h)×60=(min)</em>.

4 × 60 = 240 4.5 × 60 = 270 7.25 × 60 = 435

Then, you add the minutes worked together.

240 + 270 + 435 = 945

Then, convert the total minutes worked to ours.

945 ÷ 60 = 15.75

Finally, multiply 11.52 (the pay per hour) by 15.75 (the total hours worked)

$11.52 × 15.75h = $181.44

6 0

3 years ago

HELPPPPPPPPPPPPPPPPPPP

FrozenT [24]

Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.

Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of $x \geq 3$ . Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.

All of the other graphs have at least one point in common.
(B) has $x \leq -1$
(C) has $x = 1$
(D) has $x \leq -2$

7 0

3 years ago

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