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3 years ago

Simplify: (-2^3)^2 (there exponents signs btw :))

Mathematics

1 answer:

ollegr [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Brainliest

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Can anyone help me and show me how to get the answer to this problem 54➗6+2(8-3*4)

ss7ja [257]

I hope this helps, I wrote the new equation each time you get a new number and where it should be placed

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3 years ago

What is the surface area of the triangular prism?

Svetlanka [38]

Answer:

Step-by-step explanation:

Using pythag theorem we can find the last side of the triangle, which is equal to 5 after we have this we simply add up the areas of each individual shape like (1/2*3*4)+(1/2*3*4)+(6*5)+(3*6)+(4*6)

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3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$