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Margaret [11]
3 years ago
11

Joseph needs to find the quotient of 3,216 divided by 8. In what place is the first digit in the quotient?

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0
402 , hundreds place
Trava [24]3 years ago
4 0
The hundreds place is the answer
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Find the amplitude and the equation of the midline of the periodic function.
Masja [62]

Answer:

Option B. Amplitude =3 midline is y =2.

Step-by-step explanation:

In the graph attached we have to find the amplitude and midline of the periodic function.

Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2

=  (5-(-1))/2 = (5+1)/2 =6/2 =3.

Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.

Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.

6 0
3 years ago
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For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.
lidiya [134]

Answer: $ 125987.80

Step-by-step explanation:

Given: The value, V(t) of $393,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula

V (t)=V_o(b)^t, here V_o is the initial asset value  and b is the multiplicative decay factor.

The exponential decay function is given by ;-

f(x)=A(b)^x, where A is the initial value , x is the  times period and b is the multiplicative decay factor.

where b = 1-r, r is the rate of decay.

Since r = 15%=0.15

Therefore, b = 1-0.15=0.85

Now ,for 7 years , the value of assets is given by :-

V=393000(0.85)^7=125986.795\approx125987.80

Hence, the assets valued at after 7 years = $ 125987.80

4 0
3 years ago
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Which pair of numbers is relatively prime
mote1985 [20]

Answer:

Well, Two integers are relatively prime (or coprime) if there is no integer greater than one that divides them both (that is, their greatest common divisor is one). For example, 12 and 13 are relatively prime, but 12 and 14 are not.

Step-by-step explanation:  Hope this helped! <3

6 0
3 years ago
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HELP WITH THESE QUESTIONS PART 2... 1 Question
Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

csc = \frac{hypotenuse}{opposite} = \frac{\sqrt{10}}{3}

sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

cot = \frac{adjacent}{opposite} = \frac{1}{3}

7 0
3 years ago
Help me answer this question please
enot [183]

Figure D could be formed from the net.

(bottom right)

-Because-

The net says that the middle shape (the bottom face) is 14 long, and it is 8 tall. So the only option that makes sense is the bottom right!

<em>feel free to mark brainliest! :)</em>

5 0
3 years ago
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