Move all terms not containing
|
5
−
8
x
|
|
5
-
8
x
|
to the right side of the inequality.
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Add
7
7
to both sides of the inequality.
|
5
−
8
x
|
<
8
+
7
|
5
-
8
x
|
<
8
+
7
Add
8
8
and
7
7
.
|
5
−
8
x
|
<
15
|
5
-
8
x
|
<
15
Remove the absolute value term. This creates a
±
±
on the right side of the inequality because
|
x
|
=
±
x
|
x
|
=
±
x
.
5
−
8
x
<
±
15
5
-
8
x
<
±
15
Set up the positive portion of the
±
±
solution.
5
−
8
x
<
15
5
-
8
x
<
15
Solve the first inequality for
x
x
.
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x
>
−
5
4
x
>
-
5
4
Set up the negative portion of the
±
±
solution. When solving the negative portion of an inequality, flip the direction of the inequality sign.
5
−
8
x
>
−
15
5
-
8
x
>
-
15
Solve the second inequality for
x
x
.
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x
<
5
2
x
<
5
2
Set up the intersection.
x
>
−
5
4
x
>
-
5
4
and
x
<
5
2
x
<
5
2
Find the intersection between the sets.
−
5
4
<
x
<
5
2
-
5
4
<
x
<
5
2
The result can be shown in multiple forms.
Inequality Form:
−
5
4
<
x
<
5
2
-
5
4
<
x
<
5
2
Interval Notation:
(
−
5
4
,
5
2
)
(
-
5
4
,
5
2
)
Plug in 3 for x
f(3) = 2(3) + 1
f(3) = 6 + 1
Solution is 7
Answer:
Step-by-step explanation:
What you are doing is removing the brackets. That shows up as multiplying both terms inside the brackets by the factor outside the brackets (2).
This is a classic example of the distributive property.
Answer:
841
Step-by-step explanation:
Substitute 68 for all values of x:
12(68) + 25
816 + 25
= 841
Answer:
30
Step-by-step explanation:
We know that BD = 20 + 5 = 25. Let's call the point where BD and CE intersect point A. Therefore, ΔBAC ≅ ΔBAE by HL (BC = BE = 25 because they are radii, BA and AB are congruent because of the reflexive property). We can use Pythagorean Theorem to find CA. We can write CA² + 20² = 25² so CA = 15 and since CA = AE = 15 and CE = CA + CE, CE = 15 + 15 = 30.