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LuckyWell [14K]
3 years ago
10

A friend was just promoted to a new job that requires part-time travel, and he has also been promised a new laptop after his fir

st month with the company. He needs an easy way to disconnect and reconnect all his peripheral devices to his old laptop. Devices include two external monitors (one HDMI, one DVI), a USB wireless mouse, USB wireless keyboard, Ethernet network, USB printer, headphones, and microphone. He has a budget of $100. What kind of device would best suit his needs? Why? Research online to find a recommendation for a device that will work best for him. What is your recommendation and why?
Computers and Technology
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

Well, I would definitely advise him to buy USB hubs.

Explanation:

USB hub is a device that can give additional USB slot for the user just by consuming one single slots. In recent years, USB hubs can contain more than 9 slots with different variety, including HDMI and DVI that is required by this particular friend.

Using this device will make it easier to plug in and plug out all the devices he wants to his laptop since it all connected to one single hub.

Since he only has the budget under 100$ , Dell DA300 6-in-1 USB-C Hub could be a good option for Him.

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3 years ago
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koban [17]

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g Create a package named lab7 (no spaces, ALL in lowercase) where you will place your lab files. Write a class FilterWith with a
sweet [91]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

import java.util.Scanner;

public class ListFilter

{

public static void filterRange(ArrayList<Integer> list,int min, int max)

{

ArrayList<Integer> listNew=new ArrayList<Integer>();

for(int i=0;i<list.size();i++)

{

if(list.get(i)>=min && list.get(i)<=max) //Checking if element is between min and max

{

listNew.add(list.get(i));

}

}

list.removeAll(listNew); //removing all elements from list.

}

public static void main(String[] args)

{

ArrayList<Integer> list=new ArrayList<Integer>();

list.add(4);

list.add(7);

list.add(9);

list.add(2);

list.add(7);

list.add(7);

list.add(5);

list.add(3);

list.add(5);

list.add(1);

list.add(7);

list.add(8);

list.add(6);

list.add(7);

Scanner sc=new Scanner(System.in);

System.out.println("Enter min : ");

int min=sc.nextInt();

System.out.println("Enter Max : ");

int max= sc.nextInt();

filterRange(list, min, max);

//Displaying new List

for(int i=0;i<list.size();i++)

{

System.out.print(list.get(i)+" ");

}

}

}

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What should be done to make sure the AutoSum feature will use the correct range?
morpeh [17]

Answer:

a

Explanation:

3 0
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