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2 years ago

14

A resturant serves a 20 ounce steak. how much does the steak weigh in pounds and ounces

2 answers:

scoundrel [369]2 years ago

8 0

1 pound and 4 ounces, or 1.25 pounds.

Oliga [24]2 years ago

3 0

There are 16 ounces in a pound.

Therefore, a 20 ounce steak is 1 pound 4 ounces.

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stealth61 [152]

Given:

The figure of a triangle DEF.

To find:

The coordinate of image of given triangle after reflection over y-axis.

Solution:

The vertices of given triangle are D(1,4), E(4,3), F(2,0).

If a figure is reflected over the y-axis, then the rule of reflection is

$(x,y)\to (-x,y)$

Using this rule, we get

$D(1,4)\to D'(-1,4)$

$E(4,3)\to E'(-4,3)$

$F(2,0)\to F'(-2,0)$

Therefore, the coordinates of image are D'(-1,4), E'(-4,3) and F'(-2,0).

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Slav-nsk [51]

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SVETLANKA909090 [29]

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2 years ago

Ayden has a goal of finishing painting at least 80% of the 500 square meters of a houses walls by today. He actually finished pa

svlad2 [7]

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Step-by-step explanation:

80% of 500 square meters is 400 square meters. Ayden has painted 415 square meters which is 83%.

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2 years ago

4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t

Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

$a_{n}=a_{1}r^{n-1}$

$a_{1}$ = the first term of the series

$r$ = the geometric ratio

$a_{1}$ would represent the height at which the ball is first dropped. Therefore:

$a_{1} = k$

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

$r=\frac{3}{4}$

Our general term would be:

$a_{n}=a_{1}r^{n-1}$

$a_{n}=k(\frac{3}{4}) ^{n-1}$

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

$k$ represents the initial height:

$k = 235\ ft$

$n$ represents the number of times the ball bounces:

$n = 6$

Plugging this back into our general term of the geometric series:

$a_{n}=k(\frac{3}{4}) ^{n-1}$

$a_{n}=235(\frac{3}{4}) ^{6-1}$

$a_{n}=235(\frac{3}{4}) ^{5}$

$a_{n}=55.8\ ft$

$a_{n}$ represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. 

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

$S_{n}=\frac{a_{1}(1-r^{n})}{1-r}$

We already know these variables:

$a_{1}= k = 235\ ft$

$r=\frac{3}{4}$

$n = 12$

Therefore:

$S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }$

$S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }$

$S_{n}=(4)(235)(1-\frac{3}{4} ^{12})$

$S_{n}=910.22\ ft$

8 0

2 years ago