L ≥ 5w + 4
2(L+w) ≥ 32
L+w ≥ 16
6w + 4 ≥ 16
6w ≥ 12
w ≥ 2
L ≥ 5w + 4
L ≥ 14
If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.
Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!
I don't understand the question
Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
Answer:
The range is found by subtracting the lowest number (44) from the highest number (75). 75-44=31 So your range is 31
Step-by-step explanation:
