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kotykmax [81]
3 years ago
9

Help ASAP please and explain

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

37

Step-by-step explanation:

There are 2 ways to do this, the first is to just count the number of shaded squares (35)

The second is to find the area of the larger shaded square and subtract the smaller un-shaded rectangles

The large square is 7x7=49 squares

There are two 2x3 rectangles, which are 6 each

49-6-6=37

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Step-by-step explanation:

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A publisher reports that 65% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
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Answer:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

Step-by-step explanation:

Information given

n=340 represent the random sample taken

\hat p=0.60 estimated proportion of readers owned a laptop

p_o=0.65 is the value that we want to test

z would represent the statistic

p_v{/tex} represent the p valueHypothesis to testWe want to check if the true proportion of readers owned a laptop if different from 0.65&#10;Null hypothesis:[tex]p=0.65  

Alternative hypothesis:p \neq 0.65  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

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4 years ago
Josh will take 10 tests in five weeks at school how many tests will he have taken after seven weeks
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C. $30.00 is the answer !!!!!!
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