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nevsk [136]
3 years ago
7

you worked on a school project every day for 5 days each day you worked for 3 hours in the morning and 4 hours in the afternoon

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0
If you are asking for how many hours you work, then:

5(3+4)=5*7=35 hours total
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Find Ms. Buggie's mistake in the following problem. Then, give what the correct answer should be.
sdas [7]

Answer:

Mrs. Buggie should have Subtracted 13 instead of adding 13

LKA = 94°

Step-by-step explanation:

Lets work backwards from the equation so far:

40 = x+ 13

x + 13 = 40

We should subtract 13 because we are adding a number and 13 to 40

Imagine this:

You have 5 apples, but you bought some more and now you have 10

equation would be:

5+x = 10

subtract 5 from 10 to get 5

So you bought 5 apples

Back to the Question:

40 - 13 = 27

3(27) + 13 = 81+13 = 94°

Answer = 94°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
PLS HELP IF YOU ANSWER I WILL GIVE YOU BRAINLIEST ANSWER
Elodia [21]

Answer:

4.5

Step-by-step explanation:

7 0
2 years ago
How many ounces are in 3 1/2 pounds and 4 ounces
Shkiper50 [21]

60 oz

Step-by-step explanation:

Although 60 is the correct answer, you might want to double check because you just used two different systems of measurement in one problem.

8 0
3 years ago
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
If anyone understands can you please help me✨‍♀️
sergiy2304 [10]
180 mins to walk 12 miles :)
4 0
3 years ago
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