Answer:
The solution is x=1,y=2,z=3
Step-by-step explanation:
The given system of equations is ;\
2x−3y+4z=8...(1)
3x+4y−5z=−4...(2)
4x−5y+6z=12...(3)
Make x the subject in equation (1)

Put equation (4) into equation (2) and (3)

Multiply through by;

Expand;

Simplify;

Equation (4) in (3)





Put equation (6) into equation (5)




z=3
Put z=3 into equation (6)
y=2(3)-4=2
Put y=2 and z=3 into equation 4

The solution is x=1,y=2,z=3
Answer:
HCF (HIGHEST COMMON FACTOR) OR GCF ( GREATEST COMMON FACTOR) OF 40 AND 60 IS 20.
Answer:-3/2
Step-by-step explanation:
-2 2/6+5/6
-7/3 + 5/6
(2x-7+1x5) ➗ 6
(-14+5) ➗ 6
-9 ➗ 6
-9/6=-3/2
Answer:
((2a+b)/2 , a/2)
Step-by-step explanation:
The midpoint is the mean/average of both the x and y values.
Our x values are a+b and a
Our y values are a-b and b
The midpoint x value is (a+b + a ) /2 = (2a + b)/2
The midpoint y value is (a-b + b) /2 = (a)/2
The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint
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Step-by-step explanation: